University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 9 - Section 9.10 - The Binomial Series and Applications of Taylor Series - Practice Exercises - Page 553: 81

Answer

Radius of convergence is: $\dfrac{2}{3}$

Work Step by Step

We need to apply the Ratio Test to the series. $\lim\limits_{n \to \infty} |\dfrac{u_{n+1}}{u_n}|=\lim\limits_{n \to \infty} |\dfrac{(3n+1)x}{2n+2}|$ or, $=|x| \lim\limits_{n \to \infty} (\dfrac{(3n+2)}{2n+2})$ or, $=|x| \lim\limits_{n \to \infty} (\dfrac{(3+2/n)}{n+2/n})$ So, $=\dfrac{3}{2}|x|$ The series converges absolutely for $\dfrac{3}{2}|x| \lt 1$ or, $|x| \lt \dfrac{2}{3}$ So, the radius of convergence is: $\dfrac{2}{3}$
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