Answer
$(4,-3,5)$
Work Step by Step
Since, we have $\overrightarrow{AB}=i+4j-2k$ and suppose $A=(p,q,r)$
$\overrightarrow{AB}=(5-p)i+(1-q)j+(3-r)k=i+4j-2k$
Now, $5-p=1, 1-q=4, 3-r=-2$
Thus, $p=4,q=-3,r=5$
Hence, $A=(4,-3,5)$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 11 - Section 11.2 - Vectors - Exercises - Page 609: 39
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