Answer
a) $2i$;
b) $-\sqrt 3k$;
c) $\dfrac{3}{10}j+\dfrac{2}{5}k$
and
d) $6j-2j+3k$
Work Step by Step
Here, a) $2(i)=2i$;
b) $\sqrt 3(-k)=-\sqrt 3k$;
c) $\dfrac{1}{2}(\dfrac{3}{5}j+\dfrac{4}{5}k)=\dfrac{3}{10}j+\dfrac{2}{5}k$
and
d) $7(\dfrac{6}{7}i-\dfrac{2}{7}j+\dfrac{3}{7}k)=6j-2j+3k$
