Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 7: Transcendental Functions - Section 7.6 - Inverse Trigonometric Functions - Exercises 7.6 - Page 420: 16

Answer

$-\displaystyle \frac{\pi}{2}$

Work Step by Step

$y=\tan^{-1}x$ is the number in $(-\pi/2, \pi/2)$ for which $\tan y=x.$ In $(-\pi/2, \pi/2)$, we want the angle (in radians) for which $\tan x\rightarrow+\infty$. This is $-\displaystyle \frac{\pi}{2}$. Alternatively, we can reach the same conclusion by observing the graph of $y=\tan^{-1}x$ (also written as $\arctan x$) when $ x\rightarrow-\infty$. See below.
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