Answer
$\dfrac{5}{7}$
Work Step by Step
Consider: $\lim\limits_{x \to \infty}f(x)=\lim\limits_{x \to \infty}\dfrac{5x^2-3x}{7x^2+1}$
Need to check that the limit has an indeterminate form.
Thus, $f(\infty)=\dfrac{\infty}{\infty}$
Now, apply L-Hospital's rule such as: $\lim\limits_{a \to b}f(x)=\lim\limits_{a \to b}\dfrac{g'(x)}{h'(x)}$
This implies:
$\lim\limits_{x \to \infty}\dfrac{10x-3}{14x}=\dfrac{\infty}{\infty}$
Again apply L-Hospital's rule.
$\lim\limits_{x \to \infty}\dfrac{10}{14}=\dfrac{10}{14}=\dfrac{5}{7}$
