Answer
20/3
Work Step by Step
Integrate with respect to x, and then plug in the limits:
$=\frac{1}{3}x^3-x^2+3x$ with limits from -1 to 1
$=\frac{1}{3}(1)^3-1+3-\frac{1}{3}(-1)^3+(-1)^2-3(-1)=1/3+2+1/3+1+3=20/3$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 5: Integrals - Section 5.4 - The Fundamental Theorem of Calculus - Exercises 5.4 - Page 286: 2
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
