Answer
4
Work Step by Step
$\int^{\frac{\pi}{0}}_{0}4\frac{sin u}{cos^2u}du$
$=\frac{4}{cosu}]^{\frac{\pi}{3}}_0$
=$\frac{4}{\frac{1}{2}}-\frac{4}{1}$
=4
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 5: Integrals - Section 5.4 - The Fundamental Theorem of Calculus - Exercises 5.4 - Page 286: 12
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