Answer
$P'(x)=na_nx^{n-1}+(n-1)a_{n-1}x^{n-2}+...+2a_2x+a_1$,
Work Step by Step
Given $P(x)=a_nx^n+a_{n-1}x^{n-1}+...+a_2x^2+a_1x+a_0$, $a_n\ne0$, using the Power Rule, we have
$P'(x)=na_nx^{n-1}+(n-1)a_{n-1}x^{n-2}+...+2a_2x+a_1$,
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 3: Derivatives - Section 3.3 Differentiation Rules - Exercises 3.3 - Page 126: 59
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