Answer
$\frac{dw}{dz}=\frac{-1}{z^{2}}-1$
$\frac{d^2w}{dz^2}=\frac{2}{z^3}$
Work Step by Step
w=$\frac{1+3z}{3z}(3-z)$
=$(\frac{1}{3}z^{-1}+1)(3-z)$
=$ z^{-1}-\frac{1}{3}+3-z $
=$ z^{-1}+\frac{8}{3}-z $
=>$\frac{dw}{dz}=-z{-2}+0-1$ =$-z^{-2}-1=\frac{-1}{z^{2}}-1$
$\frac{d^2w}{dz^2}=2z^{-3}-0=2z^{-3} =\frac{2}{z^3}$
