Answer
2
Work Step by Step
$^{\pi}_{0}\int$ $^{\pi}_{x}\int$ $\frac{siny}{y}$ dydx = $^{\pi}_{0}\int$ $^{y}_{0}\int$ $\frac{siny}{y}$ dxdy = $^{\pi}_{0}\int$ siny dy = [-cosy]$^{\pi}_{0}$ = 2
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 15: Multiple Integrals - Section 15.2 - Double Integrals over General Regions - Exercises 15.2 - Page 883: 47
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