Answer
$f_{xx}=0$
$f_{yy}=2-Cos(y)+7e^{y}$
$f_{xy}=f_{yx}=-3$
Work Step by Step
$f(x,y)=y^{2}-3xy+Cos(y)+7e^{y}$
$f_{x}=-3y$
$f_{xx}=0$
$f_{yx}=-3$
$f_{y}=2y-3x-Sin(y)+7e^{y}$
$f_{yy}=2-Cos(y)+7e^{y}$
$f_{xy}=f_{yx}=-3$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 14: Partial Derivatives - Practice Exercises - Page 864: 28
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