Answer
$1$
Work Step by Step
Consider $l=\lim\limits_{(x,y,z) \to (1,-1,e)} \ln |x+y+z|$
and $l=\ln |1+(-1)+e|$
Hence, $l=|=\ln |1-1+e|=\ln e=1$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 14: Partial Derivatives - Practice Exercises - Page 864: 13
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