Answer
$2$
Work Step by Step
Consider $l=\lim\limits_{(x,y) \to (0,0)} \dfrac{2+y}{x+\cos y}$
or, $l=\lim\limits_{(x,y) \to (0,0)} \dfrac{2+y}{x+\cos y}=\dfrac{2+0}{0+\cos (0)}$
Hence, $l=\dfrac{2}{0+1}=2$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 14: Partial Derivatives - Practice Exercises - Page 864: 10
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