Answer
$f$ is increasing on $(-\infty,0)$,
$f$ is decreasing on $(0,\infty)$.
Work Step by Step
$f'(x) = −2x$, which is zero exactly when $x = 0$. On $(−∞, 0)$ we note that $f' > 0$, so that $f$ is increasing on this interval. On $(0,∞)$, we note that $f' < 0$, so $f$ is decreasing on this interval.