Answer
$y= xe^{x^2+1}[2sin(x^3)+3xcos(x^3)]$
Work Step by Step
Chain Rule
$\frac{d}{dx}[f(g(x))] = f'(g(x)) \times g'(x)$
$y=e^{x^2+1}sin(x^3)$
Product Rule:
$y=(\frac{d}{dx}e^{x^2+1})(sin(x^3)) + (e^{x^2+1})(\frac{d}{dx}sin(x^3))$
Chain Rule:
$y=(2xe^{x^2+1})sin(x^3) + e^{x^2+1}(3x^2cos(x^3)) = xe^{x^2+1}[2sin(x^3)+3xcos(x^3)]$
