Answer
$\dfrac{64\pi}{3}$
Work Step by Step
Consider $I=\iiint_EZdV=\int_0^{2\pi} \int_{0}^{2}\int_{r^2}^{4} z \times r dr dz d\theta$
$=\int_0^{2\pi} \int_{0}^{2}[\dfrac{z^2}{2}]_{r^2}^{4} \times ( r) dr dz d\theta$
$=\int_0^{2\pi} \int_{0}^{2}[ (8r-\dfrac{r^5}{2}) dr ]dz d\theta$
$=\int_0^{2\pi}[\dfrac{8r^2}{2}-\dfrac{r^6}{12}]_{0}^{2} d\theta$
$=\dfrac{64\pi}{3}$