Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 9 - Further Applications of the Integral and Taylor Polynomials - 9.1 Arc Length and Surface Area - Exercises - Page 469: 37

Answer

$\approx 203 $

Work Step by Step

Since \begin{aligned} S&=2 \pi \int_{a}^{b} f(x) \sqrt{1+\left[f'(x)\right]^{2}} d x\\ &=2 \pi \int_{0}^{2} x^{3} \sqrt{1+\left[3 x^{2}\right]^{2}} d x \\ &=2 \pi \int_{0}^{2} x^{3} \sqrt{1+9 x^{4}} d x\\ &=\frac{\pi}{18}\int_{0}^{2}36 x^{3} \sqrt{1+9 x^{4}} d x\\ &= \frac{ \pi}{27}\left(1+9 x^{4}\right)^{3/2}\bigg|_{0}^{2}\\ &\approx 203 \end{aligned}
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