Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - Chapter Review Exercises - Page 387: 75

Answer

$$\sin^{-1}\frac{2}{3}-\sin^{-1}\frac{1}{3}.$$

Work Step by Step

We have $$\int_{1/3}^{2/3} \frac{1}{\sqrt{1-x^2}}dx =\sin^{-1}x|_{1/3}^{2/3} = \sin^{-1}\frac{2}{3}-\sin^{-1}\frac{1}{3}.$$
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