Answer
$$\frac{1}{4}(e^9-e).$$
Work Step by Step
Let $ u=4x-3$, then $ du=4dx $.
Now, we have
$$\int_1^3 e^{4x-3}dx =\frac{1}{4} \int_1^9 e^udu
= \frac{1}{4} e^u|_1^9=\frac{1}{4}(e^9-e).$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - Chapter Review Exercises - Page 387: 71
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