Answer
$\frac{1}{2}$
Work Step by Step
Let $ u=\ln x $, then $ du=\frac{1}{x}dx $.
Now, we have
$$\int_1^e \frac{\ln x}{x}dx =\int_0^1 udu
= \frac{1}{2}u^2|_0^1\\
=\frac{1}{2}(1-0)=\frac{1}{2}.$$
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