Answer
$$ g'(t)=2t \cosh t^2.$$
Work Step by Step
Since $ g(t)=\sinh t^2$, then the derivative, by using the chain rule, is given by
$$ g'(t)=\cosh t^2 (t^2)'=2t \cosh t^2.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - Chapter Review Exercises - Page 386: 39
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