Answer
$$ f'(x)=-2 (\ln 7) 7^{-2x}.$$
Work Step by Step
Recall that $(a^x)'=a^x\ln{a}$
Since $ f(x)=7^{-2x}$, then the derivative, using the chain rule, is given by
$$ f'(x)=7^{-2x}(-2x)'\ln 7=-2 (\ln 7) 7^{-2x}.$$
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