Answer
$$ h'(y)=- 2^{1-y}\ln 2.$$
Work Step by Step
Recall that $(a^x)'=a^x\ln{a}$
Since $ h(y)=2^{1-y}$, then the derivative, using the chain rule, is given by
$$ h'(y)=2^{1-y}(1-y)' \ln 2=- 2^{1-y}\ln 2.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - Chapter Review Exercises - Page 386: 27
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