Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.2 The Definite Integral - Exercises - Page 245: 46

Answer

$-\frac{15}{2}$

Work Step by Step

$\int^{5}_{0}(f(x)-x)dx=\int^{5}_{0}f(x)dx-\int^{5}_{0}xdx $ $=5-\frac{5^{2}}{2}=-\frac{15}{2}$
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