Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.2 The Definite Integral - Exercises - Page 245: 14

Answer

a) $\frac{3\pi}{4}$ b) $\frac{9\pi}{4}$

Work Step by Step

a) $\int_1^4f(x)dx$ = $\frac{1}{4}\pi(2)^{2}-\frac{1}{4}\pi(1)^{2}$ = $\frac{3\pi}{4}$ b) $\int_1^6|f(x)|dx$ = $\frac{1}{4}\pi(2)^{2}+\frac{1}{4}\pi(1)^{2}$ = $\frac{9\pi}{4}$
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