Answer
a) $\frac{3\pi}{4}$
b) $\frac{9\pi}{4}$
Work Step by Step
a)
$\int_1^4f(x)dx$ = $\frac{1}{4}\pi(2)^{2}-\frac{1}{4}\pi(1)^{2}$ = $\frac{3\pi}{4}$
b)
$\int_1^6|f(x)|dx$ = $\frac{1}{4}\pi(2)^{2}+\frac{1}{4}\pi(1)^{2}$ = $\frac{9\pi}{4}$