Answer
$\frac{24}{49}$
Work Step by Step
$\frac{dR}{dt}$ = $\frac{WT'-TW'}{W^{2}}$
W = 35, W' = -4
T = 150, T' = 0
so
$\frac{dR}{dt}$ = $\frac{(35\times0)-(150\times(-4))}{35^{2}}$ = $\frac{24}{49}$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 3 - Differentiation - 3.3 Product and Quotient Rules - Exercises - Page 122: 52
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