Answer
$-5x^{4}-\frac{1}{x^{2}}$
Work Step by Step
Using the product rule, we have
$ f'(x)=\frac{d}{dx}(\frac{1}{x}-x^{2})\times(x^{3}+1)+(\frac{1}{x}-x^{2})\times\frac{d}{dx}(x^{3}+1)$
$=(-\frac{1}{x^{2}}-2x)(x^{3}+1)+(\frac{1}{x}-x^{2})3x^{2}$
$=(-x-\frac{1}{x^{2}}-2x^{4}-2x)+(3x-3x^{4})$
$=-5x^{4}-\frac{1}{x^{2}}$