Answer
-10
Work Step by Step
$G(x)=(g(x))^{2}=g(x)\cdot g(x)$
Applying the product rule, we get
$G'(x)=g'(x)\cdot g(x)+g(x)\cdot g'(x)=2(g(x)\cdot g'(x))$
$G'(4)=2(g(4)\cdot g'(4))=2(5\times-1)=-10$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 3 - Differentiation - 3.3 Product and Quotient Rules - Exercises - Page 122: 41
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