Answer
$$ h'(s)
=(s+4)(s^2+1)+s(s^2+1)+2s^2(s+4).$$
Work Step by Step
Since $ h(s)=s(s+4)(s^2+1)$, then the derivative, using the product rule, is given by
$$ h'(s)=s'(s+4)(s^2+1)+s(s+4)'(s^2+1)+s(s+4)(s^2+1)'\\
=(s+4)(s^2+1)+s(s^2+1)+2s^2(s+4).$$