Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - Chapter Review Exercises - Page 701: 7

Answer

$$\overrightarrow{PQ}= \langle -4,1\rangle $$ $$\|\overrightarrow{PQ}\|= \sqrt{17}$$

Work Step by Step

$$\overrightarrow{PQ}=Q-P=(-3,5)-(1,4)=\langle -4,1\rangle $$ and moreover, the length is given by $$\|\overrightarrow{PQ}\|=\sqrt{(-4)^2+1^2}=\sqrt{17}$$
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