Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - 13.7 Cylindrical and Spherical Coordinates - Exercises - Page 699: 9

Answer

$(\frac{5}{\sqrt 2}, \frac{5}{\sqrt 2},2) \Longrightarrow (5, \frac{\pi}{4},2) $.

Work Step by Step

We have $$ x=\frac{5}{\sqrt 2}, \quad y =\frac{5}{\sqrt 2}, \quad z=2.$$ Now, we have $$ r=\sqrt{x^2+y^2}=\sqrt{50/2}=5,$$ $$\theta =\tan^{-1}y/x=\tan^{-1}1=\frac{\pi}{4},$$ $$ z=2.$$ So, $(\frac{5}{\sqrt 2}, \frac{5}{\sqrt 2},2) \Longrightarrow (5, \frac{\pi}{4},2) $.
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