Answer
$(1, \pi/2,-2) \Longrightarrow (0, 1,-2) $.
Work Step by Step
We have $$ r=1, \quad \theta =\pi/2, \quad z=-2.$$
Now, we have
$$ x=r\cos \theta=0,$$
$$ y=r\sin \theta=1,$$
$$ z=-2.$$
So, $(1, \pi/2,-2) \Longrightarrow (0, 1,-2) $.
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 13 - Vector Geometry - 13.7 Cylindrical and Spherical Coordinates - Exercises - Page 699: 4
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