Answer
$$ x-z=-12$$
Work Step by Step
Since $n=\langle 1,0,-1 \rangle$ and $(x_{0},y_{0},z_{0})=(4,2,-8)$
then the equation of the plane in scalar form is
$ a(x-x_{0})+b(y-y_{0})+c(z-z_{0})=0$
That is, $$(x-4)+0(y-2)-(z+8)=0$$
and simplifying it, we get
$$ x-z=-12$$
Hence the equation is given by
$$ x-z=-12.$$
