Answer
$\langle 9,-4,-11\rangle $
Work Step by Step
The normal vector of a plane in the form of:
$ax+by+cz=d $
is given as:
$\vec n=\langle a,b,c\rangle $
Therefore, the normal vector of $9x-4y-11z=2$ is $\vec n=\langle 9,-4,-11\rangle $
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 13 - Vector Geometry - 13.5 Planes in 3-Space - Exercises - Page 684: 13
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