Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - 13.5 Planes in 3-Space - Exercises - Page 684: 14

Answer

$\langle 1,0,-1\rangle $

Work Step by Step

The normal vector of a plane in the form of $ax+by+cz=d $ is given by: $\vec n=\langle a,b,c\rangle $ Therefore, the normal vector of $1x+0y-1z=0$ will equal $\vec n=\langle 1,0,-1\rangle $
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