Answer
$$2x-4y+z= -1.$$
Work Step by Step
Since $ n=\langle 2,-4,1 \rangle $ and $(x_{0},y_{0},z_{0})=(\frac{1}{3},\frac{2}{3},1)$
then the equation of the plane in scalar form is
$ a(x-x_{0})+b(y-y_{0})+c(z-z_{0})=0$
That is, $$2(x-\frac{1}{3})-4(y-\frac{2}{3})+(z-1)=0$$
and simplifying it, we get
$$2x-4y+z= \frac{2}{3}-\frac{8}{3}+1=-1$$
Hence the equation is given by
$$2x-4y+z= -1.$$
