Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - 13.1 Vectors in the Plane - Exercises - Page 650: 51

Answer

$P = \left( {4,6} \right)$

Work Step by Step

Let the coordinates of the point $P$ be $\left( {x,y} \right)$. Since the figure is a parallelogram, the following two vectors must be equivalent: $\left( {7,8} \right) - \left( {x,y} \right) = \left( {7 - x,8 - y} \right)$ ${\ \ }$ and ${\ \ }$ $\left( {5,4} \right) - \left( {2,2} \right) = \left( {3,2} \right)$ Thus, $\left( {7 - x,8 - y} \right) = \left( {3,2} \right)$. So, $P = \left( {4,6} \right)$.
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