Answer
15
Work Step by Step
The integral of $(2x^{2} + 3)$ is $((2/3)x^{3}+3x)$, so the definite integral of $(2x^{2} + 3)$ is $((2/3)1^{3} + 3(1))$ -$((2/3)(-2)^{3} + 3(-2))$, which is equal to 2/3 + 3 + 16/3 + 6, or 15.
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - 4.3 Exercises - Page 273: 8
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