Answer
84
Work Step by Step
The integral of $4x^{2}$dx is $(4/3)x^{3}$, so the definite integral of $4x^{2}$dx from 1 to 4 is $(4/3)4^{3}$ - $(4/3)1^{3}$, which is equal to 256/3 - 4/3 or 252/3 or 84.
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - 4.3 Exercises - Page 273: 6
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