Answer
0
Work Step by Step
The integral of $x^{3}$dx is $(1/4)x^{4}$, so the definite integral of $x^{3}$dx from -1 to 1 is equal to $(1/4)1^{4}$ - $(1/4)(-1)^{4}$, which is equal to 0.
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - 4.3 Exercises - Page 273: 5
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