Answer
10/3
Work Step by Step
The integral of $(x^{2} + 1)$dx is $(1/3)x^{3} + x$, so the definite integral of $(x^{2}+1)$dx from 1 to 2 is $((1/3)2^{3} + 2)$ - $((1/3)1^{3} + 1)$ is equal to 8/3 + 2 - 1/3 - 1, or 10/3.
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - 4.3 Exercises - Page 273: 7
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