Answer
$\textbf{True}$
Work Step by Step
If F(x) and G(x) are antiderivatives of f(x) then,
$$\int f(x)dx = F(x)+C_1$$ and $$\int f(x)dx = G(x)+C_2$$
By these two equations we get,
$$F(x)+C_1 = G(x)+C_2$$ or $$F(x) = G(x)+C_2 - C_1$$
$C_1$ and $C_2$ are arbitrary numbers so here it doesn't matter what their actual values are but what matters is the difference.
So let, $$C = C_2-C_1 $$ Therefore,
$$F(x) = G(x)+C$$
