Answer
The required acceleration is 7.45 ft per second per second.
Work Step by Step
Let the acceleration be a, final velocity be v, initial velocity be u and displacement be s
Using the kinematics equations, $v^{2}=u^{2}+2as$
Since the plane starts from rest, u=0, v=160 mph, s=0.7 mi
Convert 160 mph to miles per second by dividing by 3600
160 mph=$\frac{160}{3600}=\frac{2}{45}$ miles per second
Substituting, we get:
a=$\frac{\left(\frac{2}{45}\right)^{2}}{2(0.7)}$
a=$\frac{4}{2835}$ miles per second per second
a=$\frac{4}{2835}\times5280$ ft per second per second
a=7.449735 $\approx$ 7.45 ft per second per second
