Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.4 Exercises - Page 136: 52

Answer

$g'(v)=\cos{2v}.$

Work Step by Step

$g(v)=\sin{v}\cos{v}=\dfrac{\sin{2v}}{2}$ $g'(v)=2\times\dfrac{\cos{2v}}{2}=\cos{2v}.$
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