Answer
$y'=2\pi^2x\cos{(\pi x)}^2.$
Work Step by Step
$u=(\pi x)^2$; $\dfrac{du}{dx}=2\pi^2x$
$\dfrac{d}{du}f(u)=\cos{u}$
$\dfrac{d}{dx}f(x)=\dfrac{d}{du}f(u)\times\dfrac{du}{dx}=2\pi^2x\cos{(\pi x)^2}.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 2 - Differentiation - 2.4 Exercises - Page 136: 47
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