Answer
$f'(x)=\dfrac{4}{\sqrt[3]{(12x-5)^2}}.$
Work Step by Step
$u=(12x-5)$; $\dfrac{du}{dx}=12$
$f(u)=u^{\frac{1}{3}};\dfrac{d}{du}f(u)=\dfrac{1}{3\sqrt[3]{u^2}}.$
$\dfrac{d}{dx}f(x)=\dfrac{d}{du}f(u)\times\dfrac{du}{dx}=(12)\dfrac{1}{3\sqrt[3]{(12x-5)^2}}=\dfrac{4}{\sqrt[3]{(12x-5)^2}}.$
