Answer
$(1,\infty)$
Work Step by Step
$\lim\limits_{x \to 1^-} \sqrt {x-1}$ does not exist because the domain of $\sqrt {x-1}$ is $[1, \infty)$. Hence it is not differentiable at $x=1$ or less.
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 2 - Differentiation - 2.1 Exercises - Page 105: 79
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