Answer
$(-\infty, -2) \cup (-2,2) \cup (2, \infty)$
Work Step by Step
Asymptotes at $x=-2$ and $x=2$. Hence, it cannot be differentiable at $x=-2$ and $x=2$.
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 2 - Differentiation - 2.1 Exercises - Page 105: 78
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