Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 11 - Three-Dimensional Space; Vectors - 11.1 Rectangular Coordinates In 3-Space; Spheres; Cylindrical Surfaces - Exercises Set 11.1 - Page 771: 9

Answer

Ans. Radius=√74 Coordinates of centre=(2, 1,-4)

Work Step by Step

Coordinates of diameter are A(1, -2, 4) and B (3, 4,-12) Diameter AB=$\sqrt({x_2-x_1}^2)+({y_2-y_1}^2) +({z_2-z_1}^2) $ $\sqrt({3-1}^2)+({4+2}^2) +({-12-4}^2) $ $\sqrt({x_2-x_1}^2)+({y_2-y_1}^2) +({z_2-z_1}^2) $ $\sqrt({4}^2)+({6}^2) +({-16}^2) $ $\sqrt4+36 +256 $ $\sqrt296$ $\sqrt{74}×2$ Radius=$\sqrt{74}×2$/2=√74 Centre of circle:- here o is centre of circle Let coordinates of centre be (g, h, f) g=$\frac{1+3}{2}$=2 h$\frac{-2+4}{2}$=1 f=$\frac{4-12}{2}$=-4 g, h, f=(2, 1,-4)
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