Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 11 - Three-Dimensional Space; Vectors - 11.1 Rectangular Coordinates In 3-Space; Spheres; Cylindrical Surfaces - Exercises Set 11.1 - Page 771: 8

Answer

a) If it were in 1D, there would be only one point equidistant from $x=0$ and $x=1$, and that would be the midpoint of the line segment connecting $x=0$ and $x=1$, which is $x=\frac{1}{2}$. In 3D, we have a set of points that are equidistant from $(0,0,0)$ and $(1,0,0)$. They take the form of a plane, which also bisects the line segment connecting $(0,0,0)$ and $(1,0,0)$. This is our conjecture. b) Our conjecture is true.

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